values()方法将返回字典中所有值的列表。dict1 = { "name": "feifei", "gender": "girl", "age": 28}print(dict1.values())执行结果:dict_values(['feifei', 'girl', 28])
回答于 2022-05-28 14:51
keys()方法将返回字典中所有键的列表。dict1 = { "name": "feifei", "gender": "girl", "age": 28}print(dict1.keys())执行结果:dict_keys(['name', 'gender', 'age'])
回答于 2022-05-28 14:48
使用get()方法,也可以获取字典的值dict1 = { "name": "feifei", "gender": "girl", "age": 28}x = dict1.get("age")print(x)执行结果:28
回答于 2022-05-28 11:58
通过引用其键名称(方括号内)来访问字典中的项dict1 = { "name": "feifei", "gender": "girl", "age": 28}print(dict1["age"])执行结果:28
回答于 2022-05-28 11:56
字典项中的值可以是任何数据类型字符串、整型、布尔值和列表数据类型:dict1 = { "name": "feifei", "gender": "girl", "age": 28, "isstudent":True}print(dict1)执行结果:{'name': 'feifei', 'gender': 'girl', 'age': 28, 'isstudent': True}
回答于 2022-05-28 11:52
使用len()函数获取字典的长度dict1 = { "name": "feifei", "gender": "girl", "age": 28}print(len(dict1))执行结果:3
回答于 2022-05-28 11:48
字典不能有两个具有相同键的项相同的键,后面出现的值将覆盖前面的值:dict1 = { "name": "feifei", "gender": "girl", "age": 28, "age":35}print(dict1)执行结果:{'name': 'feifei', 'gender': 'girl', 'age': 35}
回答于 2022-05-28 11:46
字典是用大括号创建,具有键值对:dict1 = { "name": "feifei", "gender": "girl", "age": 28}print(dict1)执行结果:{'name': 'feifei', 'gender': 'girl', 'age': 28}
回答于 2022-05-28 11:41
symmetric_difference_update()方法将仅保留两个集合中都不存在的元素。保留两个集合中不存在的项目:x = {"apple", "banana", "cherry"}y = {"google", "microsoft", "apple"}x.symmetric_difference_update(y)print(x)执行结果:{'cherry', 'microsoft', 'banana', 'google'}
回答于 2022-05-28 11:35